The sum of digits of a two-digits number is
13. The number obtained by interchanging
the digits is 9 more than the original number.
Find the original number.
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Answered by
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Answer:
Let x be the 10th place and y be atonic. =10x+y
x+y=13
10y+x=10x+y+9
−9x+9y=3
−x+y=1
y=x+1
x+x+1=13
2x=12
x=6
y=7
=10×6+7
=67
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