Question

the sum of digits of a two number is 10.if 18 is sbtracted from it the digits in the resulting number the number is

Answer 1

let the digit in ones place be x

and the digit in tens place be y

therefore, the two digit no. = 10y+x

the reversing no. = 10x+y

A/Q,

x+y=10

=>x=10-y

and,

10x+y=10y+x-18

=>10x-x+y-10y = -18

=> 9x-9y = -18

=> x-y = -2

=> 10-y-y=-2

=> -2y=-2-10

=> y = -12/-2= 6

x=10-6 = 4

therefore, the req. 2 digit no. = 10*6+4=64

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