The sum of digits of a two numbers is 12. The number obtained by interchanging the digits is 18, more than rhe the original number. Find the original number
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____Here's your Answer _______
Let the two number be x and y.
A.T.Q.
=> 1x + y = 12
=> y = 12 - 10x -----------(1)
Condition II,
10x + y - 10y + x = 18
=> 9y - 9x = 18
=> 9( y- x) = 18
=> y - x = 2. ---------(2)
Putting eq 1 in equation 2. we get,
=> 12 - x - x = 2
=> -2x = -10
=> x = 5--------(3)
Putting eq 3 in equation 2.
=> y - 5 = 2
=> y = 7.
Therefore ,
Two digit number = 10x + y
=> 10 × 5 + 7
=> 57.
✔✔✔
____Here's your Answer _______
Let the two number be x and y.
A.T.Q.
=> 1x + y = 12
=> y = 12 - 10x -----------(1)
Condition II,
10x + y - 10y + x = 18
=> 9y - 9x = 18
=> 9( y- x) = 18
=> y - x = 2. ---------(2)
Putting eq 1 in equation 2. we get,
=> 12 - x - x = 2
=> -2x = -10
=> x = 5--------(3)
Putting eq 3 in equation 2.
=> y - 5 = 2
=> y = 7.
Therefore ,
Two digit number = 10x + y
=> 10 × 5 + 7
=> 57.
✔✔✔
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