Question

The sum of digits of two digit number is 11. if 12 is subtracted from it, digit in resulting number will be same​

Answer 1

Step-by-step explanation:

x = 10's digit of a two digit number(Let)

y = units digit(Let)

n=Resulting equal digits(Let)

Condition 1-the sum of a two digit number is 10

x + y = 10

further simplifying

y = (10-x)

Condition 2-if 18 be subtracted from it the digits in the resulting number will be equal

10x + y - 18 = 10n + n

10x + y = 11n+ 18

Substitutituting values found above

10x + (10-x) = 11n + 18

10x - x = 11n + 18 - 10

9x = 11n+ 8

If we solve it we will found the values as - x = 7, y = 3, z = 5 and finally we can say the no. is 73.

Answer 2

Answer:

Let x = 10's digit of a two digit number

Let y = units digit

Let z = the resulting equal digits

:

Write an equation for each statement:

:

"the sum of a two digit number is 10."

x + y = 10

or

y = (10-x)

:

" if 18 be subtracted from it, the digits in the resulting number will be equal."

10x + y - 18 = 10z + z

10x + y = 11z + 18

:

Substitute (10-x) for y

10x + (10-x) = 11z + 18

10x - x = 11z + 18 - 10

9x = 11z + 8

:

The single digit integer values for x and z are limited to x=7 and z=5 in this equation:

x = 7, y = 3, z = 5

:

The number is 73

:

Check in the statement:

"if 18 be subtracted from it, the digits in the resulting number will be equal."

73 - 18 = 55

Hope it helps you!!!!!