Math, asked by amaljignu1234, 5 months ago

The sum of digits of two digit number is 11. if the digits are interchanged and the resulting number is added to original number then we get 45. what is the original number?​

Answers

Answered by Anonymous
1

Step-by-step explanation:

The sum of the digits = 11 [ Given ]

Let one digit be x. Then the other digit will be (11 - x) = y

Then the number will be 10x + (11 - x) = 9x + 11

According to the condition,

Interchanging the digits, we get

10y + x = 10(11 - x) + x = 110 - 10x + x = 110 - 9x

When adding,

110 - 9x + 9x + 11 = a

121 = a.

Maybe the question is wrong.

Possible pairs of digits with the sum of digits equal to 11 are (6,5) (7,4) (8,3) & (9,2)

When adding the interchanged digits and original number, we will get 121 only.

You may please check the sum of digits & sum of interchanged digits and original number.

If you could give it again, I would guarantee you the precise answer.

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