the sum of digits of two digit number is 11. the number obtained by interchanging the digits of the given number exceeds that number by 63. find the number
Answers
Answered by
6
Let original number =(10x+y)
reversed number=(10y+x)
x+y=11-------->(1)
10x+y=10y+x+63
9x=9y+63
x-y=7-------->(2)
from (1)and (2)
x=9
y=2
hence the number is 92
reversed number=(10y+x)
x+y=11-------->(1)
10x+y=10y+x+63
9x=9y+63
x-y=7-------->(2)
from (1)and (2)
x=9
y=2
hence the number is 92
Answered by
2
Step-by-step explanation:
92
mark me as brain list
Similar questions