Question

The sum of digits of two digit number is 12 if the digits are reversed the new number is 12 less than twice the original number .Find the original number 0

Answer 1

Answer:

let the original two Digit no. be XY

x+y=12~~~~eq(1)

if the digits are reversed the no. is YX

YX is 12 less than the original no.

YX = XY--12

10y+1x =10x+y--12

10y-y. =10x-1x--12

9y =9x--12

on dividing with 3 on both sides

3y = 3x--4

on transpoging

3x-3y=4 ~~~~eq(2)

eq(1)×3=

3x+3y=36

3x-3y=04

__-______________

6y=32

y=32/6

y= 16//3

x+y=12

x= 12-y

=12-16/3

=(36-16)/3

=20/3

now the original no. is

xy= 20/3×16/3

=320/9

I think ur sum is nt correct

so plzz check it once