the sum of digits of two digit number is 21 if the number obtained by reversing the digits is 63 more than original number find the number
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Let the 2 digits be x,y. respectively
2 digit number =10x+y
2 digit number obtained by ususing the digit =10y+x
∴10x+y+10y+x=99
⇒11x+11y=99
⇒x+y=9
x−y=3
On adding : 2x=12
x=6
putting x in ⟶(i)
6+y=9
y=3
∴ Number =10x+y=63
or , 10y+x=36.
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