Question

The sum of digits of two digit number is 8. On interchanging the digit the new number is 18 more than original number. Find the original number​

Answer 1

Step-by-step explanation:

let the number be in the form of 10x+y, where x and y are the tens digit and the units digit respectively.

Applying the first condition:, we get

x+y=8 ....(1)

Applying the second condition, given in the problem

10x+y+18=10y+x

⇒9x−9y=−18

⇒x−y=−2 ....(2)

By solving equations (1) and (2), we get

x=3 and y=5

Therefore, the number is 35

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Answer 2

Answer:

let the digit be A(in the 10 th place) and B(in the 1st place )

given

A+B= 8 ……….(1)

the no. formed by A and B is A*10+B

by interchanging the digit it will be B*10+A

so according to the question B*10+A = A*10 + B +18………..(2)

now from(1) A=8-B

putting this value of A in (2) we get

10*B+8-B=10*(8-B)+B+18

9*B+8=80–10*B+B+18

9*B+10*B-B=18+80–8

18*B=90

B=90/18

B=5

so A will be =8-B= 8–5=3