Question

the sum of digits of two digit number is 9.if 45 is added to the number the digit are reversed. find the number.​

Answer 1

The number obtained is 63

Answer 2

Answer:

27; 72

Step-by-step explanation:

let the number be 10x + y

sum of digits

x + y = 9...1

x = 9-y

reverse no =10y + x

ATQ(according to question)

10x + y +45=10y + x

10x + y -(10y + x) = -45

9x - 9y = -45

9(x - y) = -45

x - y = -5

x = -5 +y..... 2

-5 + y + y = 9

2y = 9+5

2y = 14

y = 7

therefore x =9 -7= 2

original number =10x +y

= 10*2 +7

= 20 +7

=27

reverse number =10y +x

=10*7 +2

=70 +2

=72