The sum of digits of two digits number is 9 and if tens place digit is increased by 3, the number this formed will be equal to 5/3 times the original number. What is the original number?
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Answer: original number = 45
Step-by-step explanation:
let the digit at tens place be X and the digit at units place be Y.
Any two digit no. is expressed in the form of 10X+Y.
According to the question,
X+Y=9........................(1)
(10X+30) + Y = 5(10X+Y)/3
10X+Y = 45...................(2)
From eqn-2 it is clear that our required no. is 45.
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