Question

the sum of digits of two muber is 9. also 9 times this number is twice the number obtained by reversing the order of the digits. Find the number.​

Answer 1

Answer:

18

Step-by-step explanation:

1+8=9

18x9=162

81+81=162

Answer 2

Answer:

18

Let the digits of the number be x and y .

Now , the number = 10x+y

Sum of the digits =9

So x+y = 9 --------------------(i)

Now for the next step , we have to find out the reversed number ,which will be = 10y+x

Now, According to the question ,

9(10x+y) = 2(10y +x)

90x+9y= 20y +2x

88x -11y = 0

x= 11y/88

x= 1/8 y

Now substituting the value of x in Eqn (i) , we get

1/8y+y =9

9/8 y =9

y=9×8/9

y=8

Now x = 1/8×8= 1

So the number is 10+8 = 18