Question

the sum of digits two of digits is 8 difference between and that formed by reversed the digit is 18 find the number

Answer 1

Let the one's place digit=y and ten's place digit=x
So the no.=10x+y
and the reverse of it=10y+x
And we know that the sum of the digit is 8
x+y=8
x=8-y
And we also know that the difference between the actual no. and its reversed is18
10x+y-(10y+x)=18
9x-9y=18
 Now put the value of x
9(8-y)-9y=18
72-9y-9y=18
-18y=18-72
 -18y=-54
- sign will be cancel out 
so, 18y=54
and then y=3
Hence x=5(8-3)
So the no.=5*10+3=53