The sum of eight consecutive multiples of 5 is 260. What are the eight numbers?
Answers
Answer:
Here is your answer:-
Step-by-step explanation:
N+N+2+N+4+N+6+N+8=260 These are the 5 consecutive even numbers. 5N+20=260 gather like terms together. 5N=240 Subtract 20 from each side of equation. N=48 Divide by 5 to get the smallest number amongst them, 48.
Answer:
Required eight numbers are 15,20,25,30,35,40,45,50.
Step-by-step explanation:
Given,sum of eight consecutive multiples of 5 is 260.
Let first number be x.
So, next numbers are (x+5),(x+10),(x+15),(x+20),(x+25),(x+30),(x+35),(x+40) and so on.
Now sum of first eight numbers is
According to question,
Required eight numbers are 15,20,25,30,35,40,45,50.
This is a problem of Algebra.
Some important Algebra formulas.
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab − b²
(a + b)³ = a³ + 3a²b + 3ab² + b³
(a - b)³ = a³ - 3a²b + 3ab² - b³
a³ + b³ = (a + b)³ − 3ab(a + b)
a³ - b³ = (a -b)³ + 3ab(a - b)
a² − b² = (a + b)(a − b)
a² + b² = (a + b)² − 2ab
a² + b² = (a − b)² + 2ab
a³ − b³ = (a − b)(a² + ab + b²)
a³ + b³ = (a + b)(a² − ab + b²)
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