Math, asked by jessh0320, 1 month ago

The sum of eight consecutive multiples of 5 is 260. What are the eight numbers?

Answers

Answered by siddhikrishna696
0

Answer:

Here is your answer:-

Step-by-step explanation:

N+N+2+N+4+N+6+N+8=260 These are the 5 consecutive even numbers. 5N+20=260 gather like terms together. 5N=240 Subtract 20 from each side of equation. N=48 Divide by 5 to get the smallest number amongst them, 48.

Answered by payalchatterje
0

Answer:

Required eight numbers are 15,20,25,30,35,40,45,50.

Step-by-step explanation:

Given,sum of eight consecutive multiples of 5 is 260.

Let first number be x.

So, next numbers are (x+5),(x+10),(x+15),(x+20),(x+25),(x+30),(x+35),(x+40) and so on.

Now sum of first eight numbers is

x + (x + 5) + (x + 10) + (x + 15) + (x + 20) + (x + 25) + (x + 30) + (x + 35)

 = (x + x + x + x + x + x + x + x) + (5 + 10 + 15 + 20 + 25 + 30 + 35)

 = 8x + 140

According to question,

8x + 140 = 260 \\ 8x = 260 - 140 \\ 8x = 120 \\ x =  \frac{120}{8}  \\ x = 15

Required eight numbers are 15,20,25,30,35,40,45,50.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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