the sum of either pair of opposite angles of the cyclic quadrilateral is 180
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vimalmirani74:
plz prove it
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SOLUTION____________________
Refer to the above attachment
Draw OB and OD
Now By the property
The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle......
Angle BOD = 2(Angle BAD)
Angle BAD = ½ Angle BOD _______(¹)
Similarly
Angle BCD = ½ Angle BOD ________(²)
On adding both the equations
Angle BAD + Angle BCD = ½ Angle BOD + ½ Angle BOD
Angle BAD + Angle BCD = ½ (Angle BOD + Angle BOD)
Angle BAD + Angle BCD = ½ (360°)
Angle BAD + Angle BCD = 180°
Angle A + Angle C = 180°
Similarly
Angle B + Angle D = 180°
Refer to the above attachment
Draw OB and OD
Now By the property
The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle......
Angle BOD = 2(Angle BAD)
Angle BAD = ½ Angle BOD _______(¹)
Similarly
Angle BCD = ½ Angle BOD ________(²)
On adding both the equations
Angle BAD + Angle BCD = ½ Angle BOD + ½ Angle BOD
Angle BAD + Angle BCD = ½ (Angle BOD + Angle BOD)
Angle BAD + Angle BCD = ½ (360°)
Angle BAD + Angle BCD = 180°
Angle A + Angle C = 180°
Similarly
Angle B + Angle D = 180°
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