Math, asked by vegesnapooja488, 1 year ago

The sum of exponents of the prime factors in the prime factorization of 108 is

Answers

Answered by excecutor

8

108=2^2*3^3
2+3=5. .

Answered by navinjairam37

5

Answer:

5

Step-by-step explanation:

108=2^2*3^3

sum=2+3=5

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