Question

The sum of exterior angles of a polygon is one-ninth of sun of all interior angles
Find the number of sides of the polygon.

Pls pls help .i will follow u ..and add u as the brainliest

Answer 1

Answer:

Sum of exterior angles of a polygon = 360

sum of interior angle of a polygon = (n - 2) × 180.

therefore, according to the given condition,

360 = [(n-2)×180] ÷ 9

360 × 9 = (n-2)×180

(360 × 9) ÷ 180 = n - 2

2 × 9 = n - 2

18 = n - 2

n = 18 + 2 = 20

Answer 2

Answer:

The correct option is A

20

Let the number of sides = n

Sum of exterior angles =

360∘

Sum of interior angles =(n−2)×180∘

Given,

360=19[(n−2)×180∘]

360 = (n - 2) 20

18 = n - 2

n = 20

Step-by-step explanation: