Math, asked by tushar265, 1 year ago

the sum of father age and the twice the age of bis son is 70 If we double the age of the father and add it to the age of his sum is 95 .Find their present age

Answers

Answered by Anonymous
3
let the age of the father be x
let the age of his son be y

in 1st case,
A/q,
x+2y=70---(i)

in 2nd case,
A/q,
2x+y=95-----(ii)

multiplying 2 to (i)
2x+4y=140---(iii)

(iii)-(ii)
2x+4y=140
2x+y=95
----------------
3y=45
y=15

using y=15 in (i)

x+2y=70
x+30=70
x=40....

Hope it helps u...
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Have a gr8 day ahead...

@TeraBhalaHo

tushar265: thanks
Anonymous: thank u so much
Anonymous: mark as brainliest... if my answer satisfises u
Answered by Anonymous
2
Hi.

Good Question and Keep Progressing.

Here is your answer----

________________________

Let the present age of the Father and the Son be x and y years respectively. 

According to the Question,

                    x + 2y = 70
      Thus,     x = 70 - 2y --------------------------eq(i)
Also,
               2x + y = 95 ---------------------------eq(ii)

Putting the eq(i) in eq(2),
           
             2(70 -2y) + y = 95
              140 -4y + y = 95
               140 - 3y = 95
               3y = 140 - 95
                 3y = 45
                  y = 45/3
                 y = 15 years.

Putting y = 15 years in eq(i) 
             x + 2(15) = 70
               x + 30 = 70 
              x = 70 - 30
             x = 40 years.

Thus the present age of Father = x 
                                                   = 40 years.
-------------------------------Son = y
                                            = 15 years.

___________________________

Hope it helps.

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Have a nice day.
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