the sum of father's age and twice the age of his son is 70 if we double the age of father and add it to the age of son the sum is 95 find their present ages
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Let the age of father be x years.
and
The age of son be y years.
From 1st Condition
2x+y= 70 ------- I
From 2nd Condition
x+2y=95 -------- II
Multiplying equation I by 2
therefore, we get,
4x+2y=140 --------- III
Subtract equation II from III
4x + 2y = 140
- x + 2y = 95
–―-―--------------------
3x = 45
x = 45
----
3
X = 15
Substituting X=15 in equation II
x + 2y = 95 ---- II
(15) + 2y = 95
2y = 95-15
2y = 80
y = 80
-----
2
Y = 40
The present age of father is 40 years
and
The present age of son is 15 years.
and
The age of son be y years.
From 1st Condition
2x+y= 70 ------- I
From 2nd Condition
x+2y=95 -------- II
Multiplying equation I by 2
therefore, we get,
4x+2y=140 --------- III
Subtract equation II from III
4x + 2y = 140
- x + 2y = 95
–―-―--------------------
3x = 45
x = 45
----
3
X = 15
Substituting X=15 in equation II
x + 2y = 95 ---- II
(15) + 2y = 95
2y = 95-15
2y = 80
y = 80
-----
2
Y = 40
The present age of father is 40 years
and
The present age of son is 15 years.
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