Question

The sum of father's age and Twice the age of his son is 70.if we double the age of the father and add it to the age of his son the sum is 95. Find their present ages.​

Answer 1

Answer:

Let us take the father‘s age as X and son’s age as Y

Now as given in question the sum of father’s age and twice the son’s age,

X + 2Y = 70 _______ (1)

As per given data, doubling the age of the father and adding it to the son’s age sum is 95,

2X + Y = 95 _______ (2)

Hence,

To solve (2) equation, substitute X = 70 – 2Y in X of

2X + Y =95,

2(70 – 2Y) + Y = 95

140 – 4Y + Y = 95

Y = 15

Substitute Y = 15 in X = 70 – 2Y, we get

X = 40

Answer 2

Answer:

Currently, if father's age is x and son's age is y,

then given, x+2y=70 --- (1)

2x+y=95 --- (2)

Multiplying equation (1) with 2 we get, 2x+4y=140 --- (3)

Subtracting equation (2) from (3), we get 3y=45⇒y=15

Substituting y=15 in the equation (2), we get

2x+15=95⇒x=40

Hence, the father is 40 years old and the son is 15 years old.