Question

The sum of father's age and twice the age of son is 70 and if we twice the age of father and add it to son's age it becomes 95 .Find their present ages??

Answer 1

Let the age of father be x years.
and
The age of son be y years.

From 1st Condition
2x+y= 70 ------- I

From 2nd Condition
x+2y=95 -------- II

Multiplying equation I by 2
therefore, we get,
4x+2y=140 --------- III

Subtract equation II from III

4x + 2y = 140
- x + 2y = 95
–―-―--------------------
3x = 45
x = 45
----
3

X = 15


Substituting X=15 in equation II

x + 2y = 95 ---- II
(15) + 2y = 95
2y = 95-15
2y = 80
y = 80
-----
2

Y = 40

The present age of father is 40 years
and
The present age of son is 15 years.

Answer 2

Answer:

Step-by-step explanation:

Father's age equals x

Son's age equals y

x+ 2y =70............equation1

2x+ y= 95............. equation 2

Eq 1 plus eq2

3x +3y =165

Dividing the eqn by 3

X+y=55 .......eqn 3

Eq 1-eq 2

-x+y=-15 .......eq 4

Eq3- eq4

2x=70

x=70/2=35

By eq4,-x+y=-15

y=-15+35=20