the sum of Fathers age and twice the age of his son is 70 . if we double age of Father and add it to age of his son the sum is 95 find their present ages
Sakshi1P:
nice question
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Answered by
9
Hey... I think this can be ur answer!!
Let age of father be x and that of son be y
ATQ,
x+2y =70
X= 70-2y....(1)
Now,
2x +y = 95...(2)
Substituting (1)in (2),
2(70-2y)+y=95
140 - 4y+y =95
-3y = - 45
y = 15yrs - age of son
x= 70-2(15) = 70-30 = 40yrs - age of father!!
Hope it helps you dear ☺️☺️
Let age of father be x and that of son be y
ATQ,
x+2y =70
X= 70-2y....(1)
Now,
2x +y = 95...(2)
Substituting (1)in (2),
2(70-2y)+y=95
140 - 4y+y =95
-3y = - 45
y = 15yrs - age of son
x= 70-2(15) = 70-30 = 40yrs - age of father!!
Hope it helps you dear ☺️☺️
age of son is write but age of Father is wrong
father age is 25 and son age is 22.5
yeah age of father would be 40... thx for correction.. I edited it :)
but it is not satisfying the given eqns
it is satisfying the equations
nope
what no... yes it is!!
ok
Answered by
3
Let the father's age be x, and the son's age be y.
Then, sum of fathers's age and twice the age of his son,
x+2y=70 - [I],
Sum of double the father's age and age of the son is 95,
2x+y=95 - [II]
Equation 2[I] - [II]
(2x+4y)-(2x+y)=140-95,
3y=45,
y=15
Therefore, x=40
So son's age is 15 and father's age is 40..
Then, sum of fathers's age and twice the age of his son,
x+2y=70 - [I],
Sum of double the father's age and age of the son is 95,
2x+y=95 - [II]
Equation 2[I] - [II]
(2x+4y)-(2x+y)=140-95,
3y=45,
y=15
Therefore, x=40
So son's age is 15 and father's age is 40..
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