the sum of fathers age and twist the age of his son is a 70 if we double the age of the father and add it to the age of his son the sum is 95 find their present ages
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Suppose father’s age(in years) be x and that son’s age be y.
Then,
x + 2y = 70…(I)
2x + y = 95 …(II)
Multiply Eq. I by 2 and equate,
2x + 4y = 140
-2x - y = -95 / 3y = 45
y = 45 / 3
y = 15
Substituting y = 15 in eq. (ll)
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
Son's age is 15 years.
Father's age is 40 years.
Thanks!
Suppose father’s age(in years) be x and that son’s age be y.
Then,
x + 2y = 70…(I)
2x + y = 95 …(II)
Multiply Eq. I by 2 and equate,
2x + 4y = 140
-2x - y = -95 / 3y = 45
y = 45 / 3
y = 15
Substituting y = 15 in eq. (ll)
2x + 15 = 95
2x = 95 - 15
2x = 80
x = 80/2
x = 40
Son's age is 15 years.
Father's age is 40 years.
Thanks!
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0
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