Question

the sum of first 10 term is 550 and the sum of first 5 terms is 100 write algebraic form​

Answer 1

Answer:

The sum of the first n terms of an AP is Sn = (n/2 )[2a + (n-1)·d] n = 10, S10 = -150 -150 = (10/2)[2a + (10 - 1)d] - 150 = 5[2a + 9d] Dividing through by 5, -30 = 2a + 9d ----------(1)

Answer 2

Answer:

hope it helps you

Step-by-step explanation:

let a be the first term

n = given no. of terms

Sn = [n/2][2a+(n-1)d]

S10=[10/2][2a+(10-1)d]

550=[5][2a+9d]

550=[10a+45d]

divide both sides by 5

110=[2a+9d] :this is your equation