The sum of first 10 terms in ap is 16 and the last is 60 the sum of the ap is 342 find the comnon difference
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let the a.p be a;a+d; a+2d .......a+nd
sum of 10 terms is 10a +(1+2+3+4+5+6+7+8+9)d
i.e 10a + 55d
given 10a +55d =16 .......(1)
and sum of 60a + (n+n-1 +n-2 +n-3 +........+n-59)d
i.e 60a+(60n-(1+2+3+4+......59))d
i.e 60a+ (60n-(59×60)/2)d
i.e60a+(60n-1770)d
60a+(60n-1770)d =342.....(2)
solve (1)&(2) u get the answer
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