Math, asked by apoorvasdapoorvasd, 2 months ago

the sum of first 10 terms of an arithmetic progression 5+8+11+,,,,,,,,,,is​

Answers

Answered by pramod8257
1

Answer:

aim is to fine sum of first 10 terms so n=10

let's find 10th term we called it l so

a= 1st term

n= number of terms

d = difference

d= T2-T1 =T3-T2

d= 8-5 = 11-8

d=3

sum of 10 terms=n/2(2a+(n-1)d)

= 10/2*(10+9*3)

=185

Similar questions