the sum of first 10 terms of an arithmetic progression 5+8+11+,,,,,,,,,,is
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aim is to fine sum of first 10 terms so n=10
let's find 10th term we called it l so
a= 1st term
n= number of terms
d = difference
d= T2-T1 =T3-T2
d= 8-5 = 11-8
d=3
sum of 10 terms=n/2(2a+(n-1)d)
= 10/2*(10+9*3)
=185
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