Question

the sum of first 10 terms of an arithmetic progression is 55 and the sum of first 9 terms of the same arithmetic progression is 45 then its 10th term is​

Answer 1

Answer:

sorry I don't know the answer for this question

Answer 2

Given:-

• The sum of first 10 terms of an Arithmetic Progression is 55 and the sum of first 9 terms  of the same arithmetic progression is 45.

To Find:-

• 10th term

Solution:-

We know that,

$\sf a_n = a+(n-1)d$

$\sf Sum\;of\;10 \;terms = 55$

$\sf Sum\;of\;9\;terms=45$

$\sf 10^{th}\;term=Sum\;of\;10\;term-Sum\;of\;9\;term$

$\sf 10^{th}\;term= 55 - 45$

$\underline {\boxed{\frak{10^{th}\;term=10}}} \pink\bigstar$

• Hence, the 10th term is 10

Thank you!

@itzshivani