Question

The sum of first 100 multiples of 5 is: ​

Answer 1

ap. 5,10,15........100

Sn = n/2(a+ l)

= 100/2(5+100)

=50(105)

=5250

Answer 2

Answer:

AP = 5 , 10 , 15 ..........

n= 100

d = a² - a¹

= 10-5

= 5

An = n/2{2a+(n-1)d}

An = 100/2{2×5+(100-1)5}

An = 50{10+(495)}

An = 50×505

An = 25250

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