Math, asked by roopsaraon6975, 9 months ago

The sum of first 100 multiples of 9 is

Answers

Answered by poojadevi01011974

1

Answer:

9,18,27,36....900

a=9

d=9

an=900

an=a+(n-1)d

900 = 9+(n-1)9

100=9n-9

91=9n

n= 91/9

sn= n/2(a+an)

sn= 91(9+900)

sn= 82719ans

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