the sum of first 100 natural numbers is equal to
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Let S be the required sum. Clearly, it is an Arithmetic Progression whose first term = 1, last term = 100 and number of terms = 100. Therefore, the sum of first 100 natural numbers is 5050.
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Step-by-step explanation:
use the formula=>n(n+1) /2
=100.101/2
5050
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