Math, asked by majordetective, 10 months ago

The sum of first 1000 positive
inegers is :
505000
500050
5005000
500500​

Answers

Answered by sy45764
1

Answer:

hey buddy this is the question of AP ( ARITHMETIC PROGRESSION)

SO how u gonna do this is

+ve nos are 1, 2 ,3 ,4 ... 1000

a ( mean first +ve no. ) = 1

d ( common difference ) = 1

n ( total no of terms ) = 1000

l ( last term ) = 1000

formula to find the sum is

S = n / 2 + (2a + (n-1) d). or. S = n/2 + ( a +l)

I'm using the first one

S = 500/2 + (2 ×1 + (1000 - 1) 1)

=. 250 + 2 + 999

=252 + 999

=

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