The sum of first 1000 positive
inegers is :
505000
500050
5005000
500500
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Answered by
1
Answer:
hey buddy this is the question of AP ( ARITHMETIC PROGRESSION)
SO how u gonna do this is
+ve nos are 1, 2 ,3 ,4 ... 1000
a ( mean first +ve no. ) = 1
d ( common difference ) = 1
n ( total no of terms ) = 1000
l ( last term ) = 1000
formula to find the sum is
S = n / 2 + (2a + (n-1) d). or. S = n/2 + ( a +l)
I'm using the first one
S = 500/2 + (2 ×1 + (1000 - 1) 1)
=. 250 + 2 + 999
=252 + 999
=
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