Question

The sum of first 100multiples of 6 is

Answer 1

Step-by-step explanation:

First multiple of 6 is 6

last 100 multiple of 6 is 600

a = 6

tn = 600

d = 6

tn = a + ( n - 1 ) d

600 = 6 + ( n - 1 ) 6

600 = 6 + 6n - 6

600 = 6n

n = 100

Sn = n × [ a + tn ]

2

= 100 × [ 6 + 600 ]

2

= 50 × 606

= 30300

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