Question

The sum of first 13 term of the AP :24,20,16.....is

Answer 1

Step-by-step explanation:

a=24

d=-4

n=13

sn=n/2(2a+(n-1)d)

S13=13/2(2×24+(12)×(-4)

S13=13/2(48+(-48)

S13=13/2(0)

S13=0

therefore the sum of first 13 terms of the AP is 0

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