Question

the sum of first 14 terms of an AP is 1050 first term is 20 find its tenth term​

Answer 1

Answer:

Sn = n/2[2a+(n-1)d]

1050=14/2[2(20)+(14-1)d]

1050=7[40+13d]

1050=280+91d

770=91d

therefore

d=110/13

a10=20+990/13

a10=1250/13