Question

The sum of first 14 terms of an arithmetic progression is -203.and the sum of next 11 terms is 592.Then write the Arithmetic Progression

Answer 1

Answer:

n=14

Sn= -203

S14=n/2 [2a+(n-1)d]

S11=n/2 [2a+(n-1)d]

this way you will find 'a' and 'd' now it will be easy for you.

Hope that it will help you...