the sum of first 15 terms of an A.P. is 0. it's 4th term is 12, find its 12th term.
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12.11 is twelve. .....
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S15=15/2(2a+14d)
0=30a+60d
divide by 30
a+2d=0.......1
a+3d=12.......2
2-1
d=12
a=(-24)
t12=a+11d
=(-24)+132
=(-108)
0=30a+60d
divide by 30
a+2d=0.......1
a+3d=12.......2
2-1
d=12
a=(-24)
t12=a+11d
=(-24)+132
=(-108)
beautysingh:
answer will be -12
where did i went wrong
in calculation..
its 0=a+7d instead of 2d
thanks....
understood
hi
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