The sum of first 15 terms of an ap is 112 and the sum of its next four terms is 518 find the ap
Answers
Answered by
0
Answer:
PLZ MARK AS BRAINLIEST
Answered by
84
Answer:
The sum of first 16 terms of an AP is 112 and the sum of its next fourteen terms is 518. Find the AP.
First term is - 8 and common difference is 2.
→ Sn = n/2 × [2a + (n - 1)d]
→ S16 = 16/2 × [2a + (16 - 1)d]
→ 112 = 8 × (2a + 15d)
→ 14 = 2a + 15d __(1)
Now S16 + S14 = S30
→ 112 + 518 = 630
→ S30 = 30/2 × [2a + (30 - 1)d]
→ 630 = 15 × (2a + 29d)
→ 42 = 2a + 29d __(2)
On doing eq(2) - eq(1)
→ 28 = 14d
→ d = 2
14 = 2a + 30
→ a = - 8
First term is - 8 and common difference is 2.
Similar questions