Question

The sum of first 15 terms of an arithmetic progression is 465 and the sum of

first 14 terms of the same arithmetic progression is 406. Then its 15th term is​

Answer 1

Answer:

Sn=2n[2a+(n−1)d]

750=215[2(15)+(15−1)d]

100=30+14d

∴d=1470=5

Tn=a+(n−1)d

T20=15+(20−1)5

=15+95

∴T20=110

Step-by-step explanation:

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Answer 2

Answer:

59

Step-by-step explanation:

Given: S15 = 465; S14 = 406
Difference between sum of 15 terms and 14 Terms is the last term, which is T15.
The difference, T15 = S15-S14 = 465 - 406 = 59