Question

The sum of first 15 terms of an arithmetic progression is 465 and the sum of

first 14 terms of the same arithmetic progression is 406. Then its 15th term is​

Answer 1

Answer:

Solution of given Question is given above.

p

Answer 2

Given : The sum of first 15 terms of an arithmetic progression is 465 and the sum of first 14 terms of the same arithmetic progression is 406.  

To Find : 15th term

Solution:

Let say terms of AP  are

a₁ , a₂ , a₃ , ___________________a₁₄ , a₁₅ , a₁₆  and so on

sum of first 14 terms of the same arithmetic progression is 406.  

=>  a₁ + a₂ + a₃ , ___________________+ a₁₄ = 406   ..Eq1

sum of first 15 terms of the same arithmetic progression is 465  

a₁ + a₂ + a₃ , ___________________+ a₁₄ +  a₁₅ = 465

Substituting  values from Eq1

=>   406 +  a₁₅ = 465

=> a₁₅ = 59

Hence 15th term of AP is 59

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