Question

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The sum of first 16 teram of AP, 10,6,2---------is​

Answer 1

Answer:

-320

Explanation:

a1 = 10

d = a2-a1 = 6-10 = -4

n = 16

Sn = n/2 [a1+a1+(n-1)d]

Sn = 16/2 [10+10+(16-1)-4]

Sn = 8[20+15(-4)]

Sn = 8[20-60]

Sn = 8[-40]

Sn = -320