Question

The sum of first 16 terms of A.P. 10, 6, 2, .........., is


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Answer 1

Answer:

The sum of first 16 terms of the AP: 10, 6, 2,... is (A) –320 (B) 320 (C) –352 (D) –400

Step-by-step explanation:

Answer 2

Answer:

Given

a = 10, n = 16, d = 6 − 10 = −4

We know that

Sn= n/2[2a+(n−1)d]

∴S16 = 2/16 [2×10+(16−1)(−4)]

⇒S16 = 8[20+15(−4)]

⇒S16 = 8×(−40)

⇒S16 = −320

Therefore, the sum of first 16 terms of A.P is - 320

Hope this will help you...