The sum of first 16 terms of an AP 10, 6, 2, ... is
a)320 b)-320 c)-352 d)-400
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Answered by
14
Answer:
Answer is -320
Step-by-step explanation:
Hey dr here is yr answer :-)
Given,
first term, a=10
common difference, d=6-10
= - 4
no. of terms,n = 16
now,
sn =n/2 [2a+(n-1)d]
s16 = 16/2 [2(10)+(16-1)-4]
= 8 [ 20+(-60)]
=8 [ 20-60]
=8(-40)
= -320
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