Question

The sum of first 16 terms of an AP is 120. Find the second term of another AP whose first term is 2/15 times of first terms of given AP and common difference same as common difference of given AP

Answer 1

Answer:

let a1 be the first term of another ap

and a of the given

given sum of 16 terms is 120

so 120=16/2(2a+(16-1)d

120=8(2a+15d)

120=16a+120d

15=2a+15d --(1)

as 2/15d=a1

so 15=4/15d+15d

15=4d/15+225d/15

15=229d/15

225=229d

d=0.98 --(2)

from (1) and (2) we get

15=2a+15x0.98

15=2a+14.7

2a=15-14.7

2a=0.3

a=0.3/2

a=0.15

as a1=2/15xa

so a1=2/15x0.15

a1=0.02

so the second term of another term Is a1+d

0.02+0.98

second term of another ap=1

Answer 2

Answer:

Step-by-step explanation: 2a+15=15

Given A1=2/15a

A2= 2/15a + d

15A2= 2a+15d

15A2= 15 (relationship from first statement)

Thus A2=1