Question

the sum of first 16 terms of AP 10, 7, 4, 1, ..., is

a. -400. b. -300
c. -200. d. -800

Answer 1

c is the correct answer

Answer 2

The sum of first 16 terms of A.P is -200.

Step-by-step explanation:

Given : A.P  10, 7, 4, 1, ...

To find : The sum of first 16 terms ?

Solution :

A.P  10, 7, 4, 1, ...

Here, the first term is $a=10$

The common difference is $d=7-10=-3$

The sum of n terms of A.P is

$S_n=\frac{n}{2}[2a+(n-1)d]$

The value of n is 16.

Substitute the value,

$S_{16}=\frac{16}{2}[2(10)+(16-1)(-3)]$

$S_{16}=8[20+(15)(-3)]$

$S_{16}=8[20-45]$

$S_{16}=8[-25]$

$S_{16}=-200$

Therefore, the sum of first 16 terms of A.P is -200.

So, option c is correct.

#Learn more

IN aAP: the sum of 3rd and 5th terms of an a.p is 38 and sum of 7th and 10th terms of an a.p is 83,find the a.p

https://brainly.in/question/1094936