the sum of first 16 terms of the A.P. 10,6,2,... is?
faizaankhanpatp3bt9p:
640 is the answer
a= 10 ,,,,, d = 4,,,, s16 = (16/2)(20+60)
-320
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a= 10
d= 6-10 = -4
s16 = (n/2)(2a+(n-1)d)
= (16/2)(20+(-60))
= (16 X -20)
= - 320
d= 6-10 = -4
s16 = (n/2)(2a+(n-1)d)
= (16/2)(20+(-60))
= (16 X -20)
= - 320
-320 is correct the other person is saying its 232 which is wrong
how
option mai hi ni hai 232
check ur calculation vandana u may be wrong mistakes happens even with the biggest pros
who are u marking brainliestdhirendra
Sry gay's the ans is correct
gud
np every expert make few mistakes
yes
sry
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