Question

The sum of first 16 terms of the A. P 10,6,2____IS​

Answer 1

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Given :

a=10,n=16,d=6−10=−4

We know that :

Sn=2n[2a+(n−1)d]

∴ S16=216[2×10+(16−1)(−4)]

⇒S16=8[20+15(−4)]

⇒S16=8×(−40)

⇒S16= −320

Answer : -320

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Answer 2

Answer:

-320

Step-by-step explanation:

According to your queation ,here

a:- 10 , D :- a२-a१= 6-10 = -4

n:- 16

now ,using the formula of adding of a.p

Sn = n/2 (2a+(n-1)d)

sn =16/2 (2×10 +(16-1) ×-4)

Sn = 8 (20 + (-60))

Sn= 8×-40

Sn= -320