Question

The sum of first 16 terms of the AP: 10, 6, 2,... is *

Answer 1

Step-by-step explanation:

pls refer the attachment

Answer 2

AP = 10, 6, 2, .....

a = 10

d = 6 - 10 = -4

n = 16

$s_{n} = \frac{n}{2} (2a + (n - 1)d) \\ \: \: \: \: \: = \frac{16}{2} (2 \times 10 + (16 - 1) \times - 4) \\ \: \: \: \: \: = 8(20 + 15 \times - 4) \\ \: \: \: \: \: = 8(20 - 60) \\ \: \: \: \: \: = 8( - 40) \\ \: \: \: \: \: = - 320$

Hope this helps you....

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