The sum of first 18 terms of an ap is 100 and sum of first 19 terms is 551 find ap
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Answered by
0
Answer:
t18 = a+(18-1)d
100 = a+17d
i.e, a+17d = 100__(i)
t19 = a +(19-1)d
551 = a +18d
i.e, a+18d = 551__(ii)
subtracting equation (i) & (ii)
a + 18d = 551
- a + 17d = 100
__________
d = 451
substitute d = 451 in equation (i)
a + 17×451 = 100
a + 7667 = 100
a = 100 - 7667
a = -7567
Answered by
2
Answer:
t18 = a+(18-1)d
100 = a+17d
i.e, a+17d = 100__(i)
t19 = a +(19-1)d
551 = a +18d
i.e, a+18d = 551__(ii)
subtracting equation (i) & (ii)
a + 18d = 551
- a + 17d = 100
__________
d = 451
substitute d = 451 in equation (i)
a + 17×451 = 100
a + 7667 = 100
a = 100 - 7667
a = -7567
Explanation:
Hope this answer will help you.✌️
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