the sum of first 20 odd natural numbers is equal to
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The first odd natural no: is 1.
Now let us consider this to be in an A.P. Form.
The commom difference ,d=2. (odd numbers)
Number of terms =20.
So.
Sum = 20/2 [2(1) + (20-1)2]
=10[2+38]
=10×40=400.
So 400 is your answer....
Hope it helps...
Regards,
Leukonov.
Now let us consider this to be in an A.P. Form.
The commom difference ,d=2. (odd numbers)
Number of terms =20.
So.
Sum = 20/2 [2(1) + (20-1)2]
=10[2+38]
=10×40=400.
So 400 is your answer....
Hope it helps...
Regards,
Leukonov.
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