Question

the sum of first 200 odd natural numbers​

Answer 1

Answer:

4000

Step-by-step explanation:

The number series 1, 3, 5, 7, 9, . . . . , 399. Therefore, 40000 is the sum of first 200 odd numbers.

Answer 2

Answer: 40000 is the sum of first 200 odd natural numbers.

Given: We are given a set of first 200 odd natural numbers.

To Find: We have to find the sum of them.

Step-by-Step Explanation:

We can use the formula for calculating the sum of first n odd numbers to get the sum:

The formula for calculating the sum of first n natural numbers is $n^2$

Therefore, the sum of first 200 natural numbers is:

$200^2=40000$

Alternatively,

We can use the formula for sum of AP to calculate this sum:

First 200 odd natural numbers are in AP as the common difference is 2.

First term = 1

200th term = $1+(200-1)\times2$ = $1+398=399$

The sum of n odd natural numbers = $\frac{n}{2}\times(F+L)$

where F is the first term and L is the last term.

= $\frac{200}{2}\times(1+399)=100\times400=40000$

To know more about sequence and series, refer to the links below:

https://brainly.in/question/10776726

https://brainly.in/question/29497762

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